Question
Find the LCM of x² – 8x + 15 and x² – 5x + 6
is.Solution
x² – 8x + 15 =x²-5x-3x+15 =x(x-5)-3(x-5) =(x-3)) (x-5) also x² – 5x + 6 = x²-3x-2x+6 =x(x-3)-2(x-3) =(x-2) (x-3) LCM =(x-3) (x-2) (x-5)
More HCF and LCM Questions
Question
x² – 8x + 15 =x²-5x-3x+15 =x(x-5)-3(x-5) =(x-3)) (x-5) also x² – 5x + 6 = x²-3x-2x+6 =x(x-3)-2(x-3) =(x-2) (x-3) LCM =(x-3) (x-2) (x-5)