Question

    The sum of two numbers is 156 and their HCF is 26. Find

    how many such pairs can be formed.
    A 1 Correct Answer Incorrect Answer
    B 2 Correct Answer Incorrect Answer
    C 3 Correct Answer Incorrect Answer
    D 5 Correct Answer Incorrect Answer
    E 4 Correct Answer Incorrect Answer

    Solution

    If HCF of two numbers is 26, then the two numbers are 26X & 26Y where X & Y are co-prime numbers. ⇒ H.C.F(X,Y) = 1 Now the sum of the two numbers is 156. So we can say, 26X + 26Y = 156 ⇒ X + Y = 6 The possible pairs of X & Y are: (1, 5), (2, 4), (3, 3), (5, 1), (4, 2) [As we are not considering the ordered pairs (2, 4), (4, 2), (3, 3) because X and Y are coprime] Accepted possible pairs of X & Y are: (1, 5), (5, 1) Such a number of pairs, For  (1, 5) => 26,  (26 × 5) = 130 For  (5, 1) => (26 × 5) = 130, 26 Combining the above results, So, there will be only one pair of numbers which will give the sum of two numbers is 156 and their HCF is 16 and that pair of the numbers will be (26, 130) only.

    Practice Next
    More HCF and LCM Questions

    Relevant for Exams:

    Hey, Don't leave. If you have any queries regarding any exam let us know here.

    ask-question