Question
The sum of two numbers is 156 and their HCF is 26. Find
how many such pairs can be formed.Solution
If HCF of two numbers is 26, then the two numbers are 26X & 26Y where X & Y are co-prime numbers. ⇒ H.C.F(X,Y) = 1 Now the sum of the two numbers is 156. So we can say, 26X + 26Y = 156 ⇒ X + Y = 6 The possible pairs of X & Y are: (1, 5), (2, 4), (3, 3), (5, 1), (4, 2) [As we are not considering the ordered pairs (2, 4), (4, 2), (3, 3) because X and Y are coprime] Accepted possible pairs of X & Y are: (1, 5), (5, 1) Such a number of pairs, For (1, 5) => 26, (26 × 5) = 130 For (5, 1) => (26 × 5) = 130, 26 Combining the above results, So, there will be only one pair of numbers which will give the sum of two numbers is 156 and their HCF is 16 and that pair of the numbers will be (26, 130) only.
Which of the following is responsible for seed dormancy?
Out of the following drugs, which is most common anthelmintic drug used in animals?
…………….. was established in 1972 under the Ministry of commerce and industry for promotion of export of marine products from India.
...What natural openings on the edges of leaves serve as entry points for bacterial pathogens such as Xanthomonas citri (black rot of cabbage)?
Lumpi-Pro VacInd, a vaccine for Lumpy disease of cattle has been developed by ____
The insect which is known to transmit ‘Grassy stunt virus disease’ in rice crop:
Which of the following statements is not correct regarding ionic bond?
Symptom of which nutrient deficiency appear first on older leaves and then
advance up the stem to younger leaves
Match List I with List II According to De Martonne's classification
Which of the following is not a functional of WTO?
Relevant for Exams:
