Question

The greatest number which will divide 142, 166 and 237 so as to leave 4, 5 and 7 respectively as remainders is

A 18 Correct Answer Incorrect Answer
B 21 Correct Answer Incorrect Answer
C 23 Correct Answer Incorrect Answer
D 26 Correct Answer Incorrect Answer

Solution

The required No. = 23 The greatest number will be the H.C.F. of 142-4, 166-5, and 237 - 7. HCF of 138, 161, 230 is 23 The required No. = 23

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