Question
The greatest number which will divide 142, 166 and 237
so as to leave 4, 5 and 7 respectively as remainders isSolution
The required No. = 23 The greatest number will be the H.C.F. of 142-4, 166-5, and 237 - 7. HCF of 138, 161, 230 is 23 The required No. = 23
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