Question
∆ABC and ∆DEF are similar and their areas are
respectively 49cm2 and 64cm 2 . If EF = 12 cm BC is?Solution
Ratio of perimeter of similar triangles = ratio of the corresponding sides of similar triangles. (area of ∆ABC)/(area of ∆DEF)=(BC/EF) 2 49/64 = (BC/12) 2 (7/8) 2 = (BC/12) 2 7/8 = BC/12 BC = (7 × 12)/8 = 10.5 cm
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