Question
What will be inradius of a right angle triangle whose base is 28 cm & height is 45 cm ?
By pythogorus theorem, Hypotenuse 2 = Base 2 +Height 2 = 282 + 452 = 784 + 2025 = 2809, So Hypotenuse = 53; Now inradius of a right angle triangle = (Base + Height - Hypotenuse)/2 = (28 + 45 - 53)/2 = 20/2 = 10 cmMore Geometry Questions
- In ∆ABC, AB = 5cm, BC = 10cm, and AC = 13cm then find out the value of cos A.
- Find the area of triangle having sides 20 m, 21 m, and 29 m.
- ∆ABC and ∆DEF are similar and their areas are respectively 49cm2 and 64cm 2 . If EF = 12 cm BC is?
- Question 4
- If G is the centroid and AD, BE, CF are three medians of ∆ABC with area 42 cm 2 , then the area of ∆BGD is?
- Length of a chord in a circle of radius 'r' cm, is 18 cm and distance between chord and centre of the circle is 40 cm. Find the value of (3r + 7).
- What is the ∠ SRO if O is the centre of circle, ∠ SPO = 55˚ and ∠ POR = 115 ˚
- In the figure P is a point which is 12 cm away from the centre of the circle O. A line drawn from P point cuts circle at point A and B respectively. If PB ...
- The internal bisector of ∆ABC at ∠A cuts BC on D and cuts the circum circle at E if DE = 6cm, AC = 8cm and AD = 10 cm then find the length of AB?
- If in a ΔABC, AD is internal angle bisector & D is a point on BC, AB = 9 cm, BC = 12 cm then what is BD:CD?
Relevant for Exams:
Hey! Ask a query
Please enter email id
The email must be a valid email address.
Please enter Mobile Number
Please enter valid Mobile Number
Please enter your Doubt
