Question
What will be inradius of a right angle triangle whose
base is 28 cm & height is 45 cm ?Solution
By pythogorus theorem, Hypotenuse 2Â = Base 2 +Height 2 = 282 + 452 = 784 + 2025 = 2809, So Hypotenuse = 53; Now inradius of a right angle triangle = (Base + Height - Hypotenuse)/2 = (28 + 45 - 53)/2 = 20/2 = 10 cm
I. Â 2(x+2)+ 2(-x)=5
II. Â (1/(y+1)+ 1/(y+5))=(1/(y+2)+ Â 1/(y+4))
I. 27x6 - 152x3 + 125 = 0
II. 216y6 - 91y3 + 8 = 0
I. 96x² + 52x - 63 = 0
II. 77y² + 155y + 72 = 0
I. 5q = 7p + 21
II. 11q + 4p + 109 = 0
What will be the product of smaller roots of both equations.Â
Roots of the quadratic equation 2x2 + x – 528 = 0 is
I:Â x2Â - 33x + 242 = 0
II:Â y2Â - 4y - 77 = 0
If x + 1/x = 3, find x² + 1/x².
Solve the quadratic equations and determine the relation between x and y:
Equation 1: 2x² - 8x + 6 = 0
Equation 2: y² - 7y + 10 = 0
l. p2Â - 3p - 54 = 0
II. q2Â - 19q + 90 = 0