Question
If in a ΔABC, D is a point on BC such that BD = 2 cm ,
BC = 6 cm then what is ratio of area of ΔABD to area of ΔADC ?Solution
CD = BC - BD = 6 - 2 = 4 cm So Area of ΔABD / Area of ΔADC = BD/CD = 2/4
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INURE
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