Question
The sides of a triangle are 24 cm, 26 cm and 10 cm. At
each of its vertices, circles of radius 4.2 cm are drawn. What is the area (in cm²) of the triangle, excluding the portion covered by the sectors of the circles? (π = 22/7)Solution
262 = 242 + 102 The given triangle is a right angle triangle with the length of the base and height 24 cm and 10 cm and the length of the hypotenuse is 26 cm Area of the triangle = (1/2) × 24 × 10 = 120 cm2 The radius of the circle in three vertices = 4.2 cm The total angle created in three circles in the vertices is 180° [∵ Sum of three angles of a triangle is 180°] The area of the triangle which is inside the common portion of the triangle and circle = (1/2) π (4.2)2 = 27.72 cm The area of the triangle excluding the circle is (120 - 27.72) = 92.28 cm2 ∴ The area excluding the portion covered by the section of the circles is 92.28 cm2.
15.99% of 549.99 ÷ 11.17 = ? ÷ 20.15
74.91% of 639.95 – 599.98% of 45 + 119.987 = ?
(4.88 × 5.76)2 - ?2 = 39.89 × 19.86
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exactvalue.)
(1800.23 ÷ 29.98) + (816.32 ÷ 23.9) + 1634.11 = ?
1449.98 ÷ 50.48 × 10.12 = ? × 2.16
36.05 × 5.02 + 12.052 = ? + 9.09 × 4.04Â
(31.9)3 + (34.021)² - (16.11)3 - (42.98)² = ?