Question
The lengths of three medians in a triangles are 6 cm, 8
cm, 10 cm. What is the area of that traingle (in cm 2 )?Solution
Here s = (a+ b+ c )/2 = (6 + 8 +10) /2 = 24/2 = 12 cm If a, b & c are medians of any triangle , then area of the triangle = 4/3 √(s(s - a)(s - b)(s - c)) = 4/3 √(12(12 - 6)(12 - 8)(12 - 10)) = 4/3 √(12 × 6 × 4 × 2) = (4/3) × 24 = 32 cm²
The perimeters of 2 similar triangles ∆ABC and ∆PQR are 18 cm and 12 cm respectively. If PQ= 8 cm, then AB is?
∆ABC and ∆DEF are similar and their areas are respectively 16 cm2 and 64 cm 2 . If EF = 6 cm BC is?
In the given figure CD is parallel to AB then ∠y is?
The lengths of three medians in a triangles are 24 cm, 32 cm, 40 cm. What is the area of that traingle (in cm 2 )?
- Length of a chord in a circle of radius 'r' cm, is 14 cm and distance between chord and centre of the circle is 24 cm. Find the value of (4r - 60).
The radius of a circle is 13 cm, and the length of the chord is 10 cm. Find the distance between the chord and the centre of the circle. Â
The area of an equilateral triangle is 4√3 sq m. Its perimeter isÂ
If median AD of an equilateral ∆ABC is 6 cm and G is centroid. Find AG?
What will be inradius of an equilateral triangle of side 4 cm?
The length of the each side of an equilateral triangle is 42√3. The area of incircle, (cm 2 ) is
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