In ∆ABC, AD = DB , DE is parallel to BC, and the area of ∆ABC is 24 cm2. What is the area of ∆ADE in cm2 ?
As DE is parallel to BC & AD = BC. By mid point theorem, The line segment joining the mid-points of two sides of a triangle is parallel to the third side & vice-versa, Hence E is mid point of AC so area of ∆ADE = 1/4 of ∆ABC = 1/4 of 24 = 6 cm 2
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