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As DE is parallel to BC & AD = BC. By mid point theorem, The line segment joining the mid-points of two sides of a triangle is parallel to the third side & vice-versa, Hence E is mid point of AC so area of ∆ADE = 1/4 of ∆ABC = 1/4 of 24 = 6 cm 2
If tan α = 1/2, tan β = 1/3, then find α + β.
If (sinθ+cosθ)/(sinθ-cosθ) = 2, then the value of sin4 θ is
If 3 tan X + cot X = 2√3, then find the value of 6 tan2 X + 2 cot2 X.
If A + B = 450 , then the value of 2(1 + tanA) (1 + tanB) is:
Simplify (cos13°+sin 13°) /(cos13°-sin13°)
If sin 23° = `12/13` , then tan 67° = ?
...Take θ = 450
sin2 4˚ + sin2 6˚ + sin2 8˚ + sin2 10˚ + ……… + sin2 86˚ =?