Question
The diagonals of a rectangle are inclined to one side of
the rectangle at 25°. The acute angle formed between the diagonals is:Solution
In △BOC, ∠OBC =∠OCB ----- (Opposite angle of isosceles triangle) ∠OBC+∠OCB+∠BOC = 180∘ 25∘ + 25∘ + ∠BOC = 180∘ Therefore, ∠BOC = 130∘ So, ∠AOB + ∠BOC = 180∘ ------- (Linear pair) ∠AOB = 180∘ −130∘ ∠AOB = 50∘ So, the acute angle between the diagonal is 50∘.
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