The internal bisector of ∆ABC at ∠A cuts BC on D and cuts the circum circle at E if DE = 6cm, AC = 8cm and AD = 10 cm then find the length of AB?
From the diagram, AE = AD + DE AE = 10 + 6 = 16 cm ∠ABC = ∠CED In ∆ADB and ∆AEC, (AB)/(AE ) = (AD)/(AC) (due to Similar triangle) (AB)/(16) = (10)/(8) AB = 20 cm
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