Question
Triangle ABC and triangle ACD are right angled
triangle and AB = x cm. BC = y cm, CD = z cm and x times; y = z and x, y and z has minimum integral value. The the area of ABCD is:Solution
Area of ABCD =`1/2xy+1/2xyxxsqrtx^2+y^2` for minimum integral value, put x = 3, y = 4 Area of ABCD = `1/2xx3xx4+1/2xx3xx4xx5 = 36cm^2`
More Geometry Questions
1219.98 ÷ 30.48 × 15.12 = ? × 2.16
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
`1804/898-:99/699xx749/751=?`
(√845 ×19.932+ √4230 ×14.385)/(√1765 ×4.877 ) = ?
Direction: Please solve the following expression and choose the closest option
`(13.022)^(2)+ (42.93)^(2)-(53.125)^(2)+(192.33xx14.88)=?- (88.44)^(2)- (42.03 xx 23.12)`
√49 + 6.66% of 1725 + 22² = ?² - √361Â
What approximate value will replace the question mark (?) in the following?
? =...
? = 49.97% of 38.09% of 1998.95
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
