Question
Triangle ABC and triangle ACD are right angled
triangle and AB = x cm. BC = y cm, CD = z cm and x times; y = z and x, y and z has minimum integral value. The the area of ABCD is:Solution
Area of ABCD =`1/2xy+1/2xyxxsqrtx^2+y^2` for minimum integral value, put x = 3, y = 4 Area of ABCD = `1/2xx3xx4+1/2xx3xx4xx5 = 36cm^2`
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