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      Question

      (I) 3x2 - 7x + 2 = 0 (II) 2y2 -

      11y + 15 In the following questions two equations numbered I and II are given. You have to solve both the equations. Give answer if;
      A x < y Correct Answer Incorrect Answer
      B x > y Correct Answer Incorrect Answer
      C x=y Correct Answer Incorrect Answer
      D xβ‰₯y Correct Answer Incorrect Answer
      E x≀y Correct Answer Incorrect Answer

      Solution

      1. 3x2 - 7x + 2 = 0 or 3x2 - 6x - x + 2 = 0
      ( x - 2) (3x -1) = 0, x= 2, 1/3 II. 2y2 - 11y + 15 = 0 or 2y2 - 6y - 5y + 15 = 0 2y( y - 3) - 5 (y – 3) = 0, or (2 y – 5) ( y – 3) = 0 = 5/2 , 3 Hence y >x .

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