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    Question

    (I) 3x2 - 7x + 2 = 0 (II) 2y2 -

    11y + 15 In the following questions two equations numbered I and II are given. You have to solve both the equations. Give answer if;
    A x < y Correct Answer Incorrect Answer
    B x > y Correct Answer Incorrect Answer
    C x=y Correct Answer Incorrect Answer
    D xтЙеy Correct Answer Incorrect Answer
    E xтЙдy Correct Answer Incorrect Answer

    Solution

    1. 3x2 - 7x + 2 = 0 or 3x2 - 6x - x + 2 = 0
    ( x - 2) (3x -1) = 0, x= 2, 1/3 II. 2y2 - 11y + 15 = 0 or 2y2 - 6y - 5y + 15 = 0 2y( y - 3) - 5 (y – 3) = 0, or (2 y – 5) ( y – 3) = 0 = 5/2 , 3 Hence y >x .

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