The Speed of two cyclists follow a ratio of 9:5. If the slower cyclist covers a distance of 480 km in 6.4 hours, determine the time it takes for the faster cyclist to travel 540 km.
ATQ, Let the speed of faster cyclist and slower cyclist be 9p km/hr and 5p km/hr, respectively Also, speed of slower cyclist = (480/6.4) = 75 km/hr Therefore, speed of faster cyclist = 75 × (9/5) = 135 km/hr Required time taken = (540/135) = 4 hours
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