If in school B, number of female students is 25% of the total number of students and ratio of male and female teachers is 5:7, and then find the difference of total number of female students and male teachers in company B together.
In school A, Let number of students and teachers be 5x and 3x respectively. Now, 5x – 3x = 400 => x = 200 Total number of students = 5x = 1000 Total number of teachers = 3x = 600 Now, 2a = 1000 => a = 500 In school B, Let number of students and teachers be 7x and 9x respectively. Now, 9x – 7x = 320 => x = 160 Total number of students = 7x = 1120 Total number of teachers = 9x = 1440 Now, b + 340 = 1120 => b = 780 In school C, Here, m = 90 => n – m = 160 [n > m given] => n – 90 = 160 => n = 250 Total number of students = 90 Total number of teachers = 250 In school D, Let number of students and teachers be 4x and 5x respectively. Now, 5x – 4x = 100 => x = 100 Total number of students = 4x = 400 Total number of teachers = 5x = 500 Now, c2 = 400 => c = 20 In school B, Number of female students = 25% of 1120 = 280 Number of male teachers = 1440 × (7/12) = 840 Required difference = 840 – 280 = 560
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