Question
A man invested a sum of Rs 25,000. He invested some part
at 5 % p.a. and remaining at 5.5% p.a. How much money did he invest at 5 % p.a.? Statement I: The total interest amount paid after 1 year was Rs 1300 Statement II: The interest on one sum was twice that on the other. In each of the following questions, a question is followed by two statement. Read all the statements and find that which statements are required to answer the question and answer accordingly.Solution
Let the first part is Rs x, then remaining part is Rs (25000 - x) From statement I, [(5 ×1 ×x)/100] + [((25,000 -x) ×1 × 5.5)/100] = 1300 -(0.5 x)/100 = - 1375 + 1300 So -0.5x/100 = -75 x = 15,000 From statement II, [(5 ×1 ×x)/100] = 2 [((25,000 -x) ×1 × 5.5)/100] (5 x)/100 = (275000 - 11x)/100 16 x = 275000 x = 17187.50 So answer can be determined by either of statement I or II.
28(4/5) + 52(1/2) × 8(2/7) - 11(1/5) = ? + 6(1/5)
What is (0.08% of 0.008% of 8)1/9 ?
3% of 3000 x ?% of 2000 = 3600
(62 - 52 ) % of 800 = 22 X β?
1500 Γ· 15 + 1000 Γ· β100 + ? = 250 * 3
β(24 Γ 5 Γ· ?) Γ 4 = 56 + 34 β 10
242 + 18 Γ 8 β ? = 356
1.25 Γ 36 + 2.75 Γ 40 = ? Γ 3.1
4.004 + 5.7(2.5 – 0.5) =?
48 Γ· 6 Γ β25 + 13 Γ 8 = ?