Question
A bag contains 5 red books, 7 yellow books
and 7 green books . 3 books are drawn randomly. What is the probability that the books drawn is not a green book ?Solution
Total number of books = 5 + 7 + 7 = 19 Let S be the sample space. Then, n(S) = number of ways of drawing 3 books out of 19 = 19C3 = `(19 xx 18 xx 17)/ (3 xx 2 xx 1)` = 969 Let E= event of drawing no green books n(E) = 12C3 = `(12 xx 11 xx 10)/(3 xx 2 xx 1)` = 220 `:.` P(E) = `(n(E))/(n(S))` = `220/969`
What will be the next number in the series?
2,5,11,23,47,?
12, 23, 68, 271, 1354, ?
24, 33, 50, ?, 108, 149
Direction: Which of the following will replace ‘?’ in the given question?
342, ‘?’, 420, 462, 506, 552, 60
16 18 14 20 12 ?
...The question below is based on the given series I. The series I satisfy a certain pattern, follow the same pattern in series II and answer the questions...
85    135    172    ?     215    225
Complete the series choosing the missing number.
8, 13, 20, ____, 40.
1 2 9 ? 65 126
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10      �...
