Question
A bag contains x red, (x+4) blue, and (x+8) green balls.
If the probability of getting a blue ball is 1/8 more than that of getting a red ball, then find the probability of getting a green ball.Solution
ATQ, 
Total balls = x+(x+4)+(x+8) = 3x+12 = 32. Probability of getting a green ball = (x+8)/(3x+12) = 28/32 = 7/8
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