Question
A bag contains 3 Red, 3 Blue and 6 Green balls. Two
balls are drawn at random. What is the probability that 1 ball is red and other is blue or 1 ball is green and other is red?Solution
Probability = (1 red ball and 1 blues ball) or (1 green ball and 1 red ball)
=> [( 3 C 1 Â *Â 3 C 1 ) + ( 6 C 1 Â *Â 3 C 1 )]/ 12 C 2
=> 27/66 =Â 9/22
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