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    Question

    A bag contains 3 Red, 3 Blue and 6 Green balls. Two

    balls are drawn at random. What is the probability that 1 ball is red and other is blue or 1 ball is green and other is red?
    A 27/35 Correct Answer Incorrect Answer
    B 9/35 Correct Answer Incorrect Answer
    C 1/2 Correct Answer Incorrect Answer
    D 9/22 Correct Answer Incorrect Answer
    E None of these Correct Answer Incorrect Answer

    Solution

    Probability = (1 red ball and 1 blues ball) or (1 green ball and 1 red ball)

    => [( 3 C 1  *  3 C 1 ) + ( 6 C 1  *  3 C 1 )]/ 12 C 2

    => 27/66 = 9/22

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