Let breadth and height of the room be b and h respectively. From I, Area of the four walls of the room = 2(10 + b)h = 6400/25 ⇒ 2(10 + b)h = 256 ⇒ (10 + b)h = 128 m……… (i) From II, 10 × b = 8400/140 ⇒ b = 8400/(140 ×10) = 6 m………(ii) By putting the value of b in equation (i), we get (10 + 6)h = 128 m ⇒ h = 128/16 = 8m. Therefore, both statement I and statement II together is required to answer the question.
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