Question
A principal amount is invested at an annual compound
interest rate of y%. After 2 years, the investment grows to Rs. 7200, and after 4 years, it reaches Rs. 10368. Determine the value of 'y'.Solution
Let the sum invested = Rs. K We have, K X {1 + (y/100)}2 = 7200 And, K X {1 + (y/100)}4 = 10368 So, 10368 ÷ 7200 = [K X {1 + (y/100)}4] ÷ [K X {1 + (y/100)}2] Or, 1.44 = {1 + (y/100)}2] = {(100 + y)/100}2 Or, {(100 + y)/100} = √1.44 = 1.2 Or, 100 + y = 120 So, y = 20 Hence, option a.
What value should come in place of (?) question mark in the given expression.
17 × 15 − 96 ÷ 8 + 6² = ?
Evaluate: 144 ÷ 12 × 6 + 35 − 4²
What will come in the place of question mark (?) in the given expression?
21 × 18 + ? – 19 × 15 = 25 × 24
2916 ÷ 54 = ? + 27
√324 + √484 + 63 = ?2Â
What will come in the place of question mark (?) in the given expression?
{(2/15) + (12/25)} of 375 + 190 = ?% of 375
- What will come in place of the question mark (?) in the following questions?
100−[20+4×5]=? (72 × 52 + 1555 )/(79+60) = 2000 ÷ ?
72 × 2 = ? + 104 – 14
672 ÷ 28 × 24 + 363 – 309 =?
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