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Let the sum invested = Rs. K We have, K X {1 + (y/100)}2 = 7200 And, K X {1 + (y/100)}4 = 10368 So, 10368 ÷ 7200 = [K X {1 + (y/100)}4] ÷ [K X {1 + (y/100)}2] Or, 1.44 = {1 + (y/100)}2] = {(100 + y)/100}2 Or, {(100 + y)/100} = √1.44 = 1.2 Or, 100 + y = 120 So, y = 20 Hence, option a.
98, 122, 182, 278, 410, ?
70, 95, 145, ?, 320, 445
4, 7, 12, 21, 36, ?
140, 146, 158, 176, ?, 230
63, 74, ?, 129, 173, 228
What will come in the place of questions (?) mark in the following questions.
160, 223, 271, 306, 330, ?
100 180 294 448 648 ?
23 44 64 83 ? 118
...120, 157, 116, 159, ?, 165
47, 72, 122, ?, 297, 422