Question
In a circle, two chords AB & CD are produced at P which
is outside the circle . If PA= 12 cm, AB= 10 cm , PC = 2 cm then find CD.Solution
We know that when AB & CD two chords intersect at point P, PA `xx` PB = PC `xx` PD So 12 `xx` (12 + 10) = 2 `xx` (2 + CD)Â Â 264 = 2 `xx` (2 + CD)Â Â 132 = 2 + CDÂ Â CD = 130Â cm
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