Question
 From an external point P, a tangent PT is drawn to a
circle with centre O. If OP = 13 cm and radius = 5 cm, then PT is:Solution
Radius is perpendicular to tangent at the point of contact. So in right triangle OPT: OP^2 = OT^2 + PT^2 13^2 = 5^2 + PT^2 169 = 25 + PT^2 PT^2 = 144 PT = 12 cm
The simple interest on a sum of Rs 5000 at 8% per annum for 3 years is:
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