Question
In a circle, the length of a chord AB is 48 cm & radius
is 25 cm. Find the distance between centre and chord.Solution
Let AB is chord , O is centre of circle, OC is perpendicualr dran on AB So now C will be mid point of Chord. Hence AC =AB/2 = 48/2 = 24 cm& OA = radius = 25 cm So in Right angle triangle OAC , By pythagorus triplet of (7,24 & 25), OC = 7 cm
What is the height of an equilateral triangle if each side measures 8√3 cm?
- What is the average of the first eight triangular numbers?
- Determine the length of side BC if ∠BAC = 60⁰, AB= 10 cm and AC = 15 cm.
The perimeter of an equilateral triangle is 48√3 cm. Find its height.
A triangle has sides 13 cm, 14 cm, and 15 cm. Find the area of the triangle.
The altitude of an equilateral triangle is 6√3 cm. Find the area of the equilateral triangle.
- Find the distance between the parallel sides of a trapezium whose area is 315 cm² and the lengths of the parallel sides are 15 cm and 21 cm respectively.
- In triangle MNO, PQ is drawn parallel to side NO. If MP = 5 cm, PN = 10 cm and MQ = 6 cm, find MO.
- Determine the inradius of an equilateral triangle if its height is 6√3 cm.
The corresponding medians of two similar triangles are 16 cm and 20 cm. If the area of the first triangle is 288 cm, then find the area of the second tr...