Question
A chord of a circle is 16 cm long and its distance from
the centre is 6 cm. The radius of the circle is:Solution
ATQ, Perpendicular from centre to chord bisects the chord. Half chord = 16/2 = 8 cm Using Pythagoras: Radius^2 = 8^2 + 6^2 = 64 + 36 = 100 Radius = 10 cm Answer: C. 10 cm
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