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    Question

    In the given figure, AB is diameter and CD ∥ AB. If

    the value of ∠BPC is 55°, then find the value of ∠BCD.  
    A 55° Correct Answer Incorrect Answer
    B 45° Correct Answer Incorrect Answer
    C 35° Correct Answer Incorrect Answer
    D 30° Correct Answer Incorrect Answer

    Solution

      Here, ∠APC = 90° (∵ angle in semicircle is 90°) Now, ∠APC = 90° - 55° = 35° and, ∠APC = ∠ABC Then, ∠ABC = ∠BCD = 35°

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