Question
In the given figure, AB is diameter and CD ∥ AB. If the value of ∠BPC is 55°, then find the value of ∠BCD.
Here, ∠APC = 90° (∵ angle in semicircle is 90°) Now, ∠APC = 90° - 55° = 35° and, ∠APC = ∠ABC Then, ∠ABC = ∠BCD = 35°More Circle Questions
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