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Let the number of girls participated from school B and number of boys participated from school C = x Let number of boys and girls participated from school A be 2y and 3y respectively. According to question, => 2y + 3y = 180 => y = 36 Number of boys from school A = 2y = 72 Number of girls from school A = 3y = 108 Number of girls participated from school C = 3y – 18 = 90 Now, 100 + x + x + 90 = 490 => 2x = 300 => x = 150 Number of girls participated from school B and number of boys participated from school C = 150 Required ratio = 72 : 90 = 4:5
447.79 ÷ √(√2400) + 30.94 × 6.07 – 5.08 × 21.96 = ?
81% of 1550 + 27² = ? + 1386 ÷ 22
? = 200.24 + 1077.97 – 14.992
√784 × 3 + (713.99 ÷ 6.98) = ?% of 619.99
30.05% of 149.97 + ? X 8.88 = (39.95 + 12.012 - 13.0322)2
(1331)1/3 x 10.11 x 7.97 ÷ 16.32 =? + 15.022
(1096.01 ÷ 7.99) - (120.98 ÷ 10.88 X 6.99) = ? ÷ 4.99
3245.69 + ? – 3112.48 = 2654.87 – 2412.92