Question
A man rows a boat 36 km upstream and the same distance downstream. The speed of the stream is 3 km/h. It takes him 3 hours more to cover the upstream journey than the downstream journey. What is the time taken by him to row 54 km in still water?
Solution
ATQ, Let speed of boat in still water = v km/h Speed of stream = 3 km/h Upstream speed = v β 3 Downstream speed = v + 3 Given: 36/(v β 3) β 36/(v + 3) = 3 Compute LHS: 36[(v + 3) β (v β 3)] / [(v β 3)(v + 3)] = 36 Γ 6 / (vΒ² β 9) = 216 / (vΒ² β 9) So, 216 / (vΒ² β 9) = 3 β vΒ² β 9 = 216/3 = 72 β vΒ² = 81 β v = 9 km/h (take positive speed) Time to row 54 km in still water = distance / speed = 54 / 9 = 6 hours
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