Question
A boat goes 200 km with the current in 10 hours, and
returns the same distance against the current in 20 hours. Find the speed of the boat in still water.Solution
ATQ,
Speed of boat in downstream = 200 / 10 = 20 km/h Speed of boat in upstream = 200 / 20 = 10 km/h Speed of boat in still water = (20 + 10) / 2 = 30 / 2 = 15 km/h
1111.25 × 9.05 + 2323.23 × 9.05 – 2121.37 ×9.05 =?
Simplify:
0.48 ÷ 0.06 + 0.75 × (4/5)
(23 × 8) – (13 × 5) + 67 =? x 6         Â
32.5% of 40 + (13)2 + 102 = ?
Simplify the following expressions and choose the correct option.
56% of 750 − (3/8 of 320) + 15² = ?
What will come in the place of question mark (?) in the given expression?
(? ÷ 16) = (20 ÷ ?) X 20(506 ÷ 22 + 9 × 3) × ? = 900 ÷ 9
41.66% of 888 + 66.66% of 1176 = ?2 - 4√ 16 Â
5.45% of 1854 – 37.5% of 1096 = ? – 48% of 630
Find the result of
45 ÷ 3 of 6 of [12 ÷ 4 of (10 ÷ 2 + 1)] + (8 ÷ 2.5 + 1.8)
