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According to question, (a+50)/30+(b+25)/20=12 (2a+100+3b+75)/60=12 2a+3b=720–175=545 … (iii) Also, (a+90)/20+(b+70)/30=18 (3a+270+2b+140)/60=18 3a+2b=1080–410=670 … (iv) Solving equation (iii) and (iv), we get, a=125 and b=95 Therefore, required difference = 125 – 95 = 30
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