Question
The ratio of the boat's speed in
still water to the speed of the stream is 10:2. The boat takes time in the ratio 11:15 to travel (d β 70) km upstream and (d + 30) km downstream. Find the approximate value of 'd'.Solution
Let boat speed = 10x, stream speed = 2x Upstream speed = 8x, Downstream speed = 12x Upstream time = (d β 70) / 8x Downstream time = (d + 30) / 12x Given time ratio: (d β 70)/8x Γ· (d + 30)/12x = 11/15 β (12(d β 70)) / (8(d + 30)) = 11/15 β (3(d β 70)) / (2(d + 30)) = 11/15 Cross-multiply: 15 Γ 3(d β 70) = 11 Γ 2(d + 30) β 45d β 3150 = 22d + 660 β 23d = 3810 β d = 165.65 km or aprox 165 km
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