Question
Time taken by a boat to cover 253 km upstream is 49.99 %
more than the time taken by the boat to cover 340 km downstream. Total time taken in covering both these distances was 5 hours 42 seconds. Find the approximate distance covered in upstream in 3 hrs 10 sec.Solution
Let the speed of boat and stream be x km/hr and y km/hr respectively. Speed in upstream = (x – y) km/hr Speed in downstream = (x + y) km/hr ATQ: => 253/(x – y) = 3/2 × 340/(x + y) => {253/(x – y)}/{340/(x + y)} = 3/2 [ratio of time taken] Now, given that the total time taken to cover the distance is 5 hrs 42 sec or 5 hrs approx. So, 253/(x – y) = 3 and 340/(x + y) = 2 x - y = 84-----(i) x + y = 170-----(ii) solving equation (i) and (ii) we get, x = 127 y = 43 Therefore, approximate distance covered in upstream in 3 hrs 10 sec = (127 – 43) × 3 = 252 km
1885 ÷ 64.98 + 7.29 + ? = 69.09
212 + 14 × 23 – 28 × 15 = ? Â
(22² × 8²) ÷ (92.4 ÷ 4.2) =? × 32
567-4824 ÷ 134 =? × 9
Determine the value of 'p' in the expression.
28 ÷ 22p + 1 = 43Â
What will come in place of (?) in the given expression.
(15) ² - (13) ² = ?? = 6.25% of 240 + 25 2 + 17 2 – 16 × 17
35% of 840 + 162 = ? – 25% × 300
(7/5) × (3/4) × (5/9) × (6/7) × 3112 = ?
1024 ÷ 16 + 800 ÷ √64 + ? = 200 * 2