Question
Speed of a boat in still water to speed of boat in
upstream is 5:3. If the boat can travel 490 km in downstream in 5 hours, then find the time taken by the boat to cover 56 km in still water.Solution
Let speed of boat in still water and speed of boat in upstream be ‘5x’ km/h and ‘3x’ km/h, respectively. Speed of stream = 5x – 3x = 2x km/h Speed of boat in downstream = 5x + 2x = 7x km/h So, 7x = 490/5 => x = 14 Speed of boat in still water = 5 × 14 = 70 km/h Desired time = 56/70 x 60 = 48 minutes
(60/15) × 25 + 15 2 – 18% of 200 = ? 2
40% of 1820 + 80% of 630 = 90% of 1280 + ?
(750 / 15 × 15 + 152 + 20% of 125) = ?3
((67)32 × (67)-18 / ? = (67)⁸
72% of 486 – 64% of 261 = ?
The value of {5 − 5 ÷ (10 − 12) × 8 + 9} × 3 + 5 + 5 × 5 ÷ 5 of 5 is:
(25)² × 4 ÷ 5 + (3)³ + 48=? + 425
In the question, two Quantities I and II are given. You have to solve both the Quantity to establish the correct relation between Quantity-I and Quantit...
√ (573 – 819 + 775) = ? ÷ 3
- What will come in the place of question mark (?) in the given expression?
(198/13) X (52/11) - ? ÷ 5 = 13 + 68 ÷ 4
