Question
In a fixed time, a boy swims thrice the distance along
the current that he swims against the current. If the speed of the current is 4 km/hr, the speed of the boy in still water isSolution
Let the rate of swimming in still water be x km/hr Rate down-stream = (x + 4) km/hr Rate up-stream = (x – 4) km/hr According to the question, (x + 4) t = 3 (x – 4) × t x + 4 = 3x – 12 x = 8 km/hr
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