Question
A boat takes 270 minutes to travel 90 km in upstream.
The same boat in the same stream takes 120 minutes to travel 50 km in downstream. Find the distance travelled by the boat while travelling in still water for 360 minutes.Solution
Distance travelled by the boat while travelling in upstream for 1 hour = 90 × (60/270) = 20 km Distance travelled by the boat while travelling in downstream for 1 hour = 50 × (60/120) = 25 km So, upstream and downstream speed of the boat are 20 km/h and 25 km/h, respectively So, speed of the boat in still water = (20 + 25) ÷ 2 = 22.5 km/h So, distance travelled by the boat travelling in still water for 360 minutes = 22.5 × (360/60) = 135 km
If sec 4A = cosec (3A - 50°), where 4A and 3A are acute angles, find the value of A + 75.
What is the simplified value of the given expression?
3(sin² 50° + sin² 40°) + 6sin 30° - (3sec 60° + cot 45°)
Simplify:
8sin 27° sec 63° + 3cot 64° cot 26°What is the value of cosec30° sec30°?
- If tan3θ = 1, then find the value of: (sin² 2θ/sec 3θ + 15°)
- If cos θ = (4x² – 1)/(1 + 4x²) then find the value of sin q.
- sin1440° - cot630° - sin120°cos150° is equal to:
What is the value of 1/(1+tan 2 θ ) + 1 / (1+cot 2 θ ) = ?
...If sin θ + cos θ = 1.2, find the value of sin θ. cos θ.
- If sin(A + B) = 1/2 and cos(A + 2B) = 1/√2, where 0° < A, B < 90°, then find the value of tan(2A).
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