Question
A regular hexagon has a side length of 10 units. Find
the area of the hexagon.Solution
A regular hexagon can be divided into 6 equilateral triangles. The side length of each equilateral triangle is 10 units. The area of an equilateral triangle with side length s is (√3/4) * s² . So, the area of one equilateral triangle is (√3/4) * 10² = 25√3 square units. The area of the entire hexagon is 6 * 25√3 = 150√3 square units. Answer: (A)
Statements: A @ Z, Z # L, L % N, N @ U
Conclusions:
I. A @ N
II. Z @ U
III. A # L
Statements: A ≤ J ≤ K = M; Y ≥ Z > A
Conclusions:
I. J ≤ Z
II. Z ˃ Y
Statement: K = B; D ≥ L ≥ T ≥ B
Conclusion: I. D > K II. D = K
Statements: U > H ≥ W; S > T ≥ B; S < H; C ≤ D = U
Conclusions:
I. D > B
II. T < U
III. W ≤ D
Statements:
E ≥ H > O < R > U = X
Conclusions:
I. E < O
II. X = O
In the question, assuming the given statements to be true, Find which of the conclusion (s) among given three conclusions is /are definitely true and t...
In this question, the relation between various elements is shown in the statement. After the statement, two conclusions are given, select a suitable op...
Statements: A % B & G @ T $ D; W % A # P
Conclusions :Â Â Â Â Â I. D % BÂ Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â II. A % GÂ Â Â Â Â Â Â Â Â Â Â Â Â Â ...
Statements: V > R ≥ W < Z; X ≤ W; U < R ≤ Y
Conclusions:
I. X < Z
II. W < Y
III. Z > UÂ
Statements: A ≥ B ≥ C = M = N ≥ O ≤ P ≤ Y = Z
Conclusions:
I. Y > M
II. Z ≤ A
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