Question
In a company, there are three departments: A, B, and C.
The average salary of employees in department A is ₹40,000, in department B is ₹50,000, and in department C is ₹60,000. The number of employees in department A is twice that of department B, and the number of employees in department B is three times that of department C. Find the overall average salary of all the employees in the company.Solution
Let the employees in department C = x employees in department B = 3x employees in department A = 6x total salary of department A = 40,000×6x = 240,000x total salary of department B = 50,000×3x = 150,000x total salary of department C = 60,000×x = 60,000x total salary of the company = 240,000x + 150,000x + 60,000x = 450,000x Requires average = 450,000x/10x = 45,000
41.66% of 888 + 66.66% of 1176 = ?2 - 4√ 16
Evaluate: 320 − {18 + 4 × (21 − 9)}
Simplify: 72 ÷ 6 × 3 − 8 + 4
118 × 6 + 13 + 83 = ?
Simplify the following expression:
(400 +175) ² - (400 – 175) ² / (400 × 175)
150% of 850 ÷ 25 – 25 = ?% of (39312 ÷ 1512)
(75 + 0.25 × 10) × 4 = ?2 - 14
26% of 650 + 15% of 660 – 26% of 450 = ?
115% of 40 + 3 × 4 = ? × 11 – 8