Question
In a company, there are three departments: A, B, and C.
The average salary of employees in department A is ₹40,000, in department B is ₹50,000, and in department C is ₹60,000. The number of employees in department A is twice that of department B, and the number of employees in department B is three times that of department C. Find the overall average salary of all the employees in the company.Solution
Let the employees in department C = x employees in department B = 3x employees in department A = 6x total salary of department A = 40,000×6x = 240,000x total salary of department B = 50,000×3x = 150,000x total salary of department C = 60,000×x = 60,000x total salary of the company = 240,000x + 150,000x + 60,000x = 450,000x Requires average = 450,000x/10x = 45,000
564.932 + 849.029 – 425.08 = 612.095 + ?
999.99 + 99.99 + 99= ?
A sum of ₹60,000 is invested at a compound interest rate of 'x%' per annum, compounded annually, and grows to ₹75,264 in 2 ye...
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
³√? × 33.97 + 59.99 × 28.9 – 48.98 × 21.42 = 1085.344
1279.98 ÷ 40.48 × 10.12 = ? × 2.16
(124.901) × (11.93) + 219.95 = ? + 114.891 × 13.90
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
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