Question
A bowler gives 15.2 runs per wicket. He gives 32 runs
and takes 4 wickets in the last match after which his average becomes 14.4 runs per wicket. How many wickets have been taken by him before the last match?Solution
Bowling average = (Total run conceded)/(Total wicket taken) Let the total number of wickets be x Then, bowling average = 15.2 Runs conceded = 15.2x Now, (15.2x+32)/(x+4) = 14.4 15.2x + 32 = 14.4 (x + 4) 15.2x + 32 = 14.4x + 57.6 0.8 x = 57.6 – 32 x = 25.6/0.8 = 32
19.89% of 449.67 + 14.67% of 299.89 - 9.89% of 99.79 = ?
`(sqrt(960.87)xx9.932+sqrt(629.998)xx26.385)/(sqrt(1028.902)xx4.977)=?`
Find the approximate value of Question mark(?). There is no requirement to find the exact value.
? = 200.14 + 27.98 × 16.05 − (10.03)² - 12.9...
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
1299.999 ÷ 325.018 × 24.996 = ?
What approximate value should replace the question mark?
99.95 − √529 × 3 + 1439.80 ÷ 12.02 = ?
619.97 ÷ 20.01 X 124.99 ÷ 24.91 = ?
124% of 620.99 + 11.65% of 1279.23 = ?
What approximate value should replace the question mark?
9.96% of 1200.10 − 25% of 4800 = ? − 7000.20
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