Question
The average of a set of s numbers is 41. If 90 is added
to the set, then the average of the set becomes 42. Find the value of 5 X (s - 28).Solution
Sum of all 's' numbers of the set = 41 X s = '41s' ATQ; (41s + 90)/(s + 1) = 42
Or, 41s + 90 = 42s + 42 Or, 90 - 42 = 42s - 41s Or, 48 = s So, required value = 5 X (48 - 28) = 100
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