Question
The average of series 'S9', which consists of 6
consecutive even numbers, is 19. The second term of series 'T9', which consists of 5 consecutive odd numbers, is 5 more than the first term of series 'S9'. Find the average of series 'T9'.Solution
Let six consecutive even numbers be 'a', (a + 2), (a + 4), (a + 6), (a + 8) and (a + 10), respectively.
ATQ,
a + a + 2 + a + 4 + a + 6 + a + 8 + a + 10 = 19 X 6
Or, 6a = 114 - 30
So, 'a' = (84 / 6) = 14
So, 2nd term of series 'T9' = 14 + 5 = 19
So, series 'T9' = 17, 19, 21, 23, 25
Therefore, required average = (17 + 19 + 21 + 23 + 25) ÷ 5 = 21
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