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    Question

    The average of series 'S10', which consists of 6

    consecutive even numbers, is 17. The second term of series 'T10', which consists of 5 consecutive odd numbers, is 3 more than the first term of series 'S10'. Find the average of series 'T10'.
    A 15 Correct Answer Incorrect Answer
    B 16 Correct Answer Incorrect Answer
    C 17 Correct Answer Incorrect Answer
    D 18 Correct Answer Incorrect Answer

    Solution

    Let six consecutive even numbers be 'a', (a + 2), (a + 4), (a + 6), (a + 8) and (a + 10), respectively.

    ATQ,

    a + a + 2 + a + 4 + a + 6 + a + 8 + a + 10 = 17 X 6

    Or, 6a = 102 - 30

    So, 'a' = (72 / 6) = 12

    So, 2nd term of series 'T10' = 12 + 3 = 15

    So, series 'T10' = 13, 15, 17, 19, 21

    Therefore, required average = (13 + 15 + 17 + 19 + 21) ÷ 5 = 17

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