Question
The average of series 'S10', which consists of 6
consecutive even numbers, is 17. The second term of series 'T10', which consists of 5 consecutive odd numbers, is 3 more than the first term of series 'S10'. Find the average of series 'T10'.Solution
Let six consecutive even numbers be 'a', (a + 2), (a + 4), (a + 6), (a + 8) and (a + 10), respectively.
ATQ,
a + a + 2 + a + 4 + a + 6 + a + 8 + a + 10 = 17 X 6
Or, 6a = 102 - 30
So, 'a' = (72 / 6) = 12
So, 2nd term of series 'T10' = 12 + 3 = 15
So, series 'T10' = 13, 15, 17, 19, 21
Therefore, required average = (13 + 15 + 17 + 19 + 21) ÷ 5 = 17
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