Question
The average of series 'S1', which consists of 6 consecutive
even numbers, is 25. The second term of series 'T1', which consists of 5 consecutive odd numbers, is 5 more than the first term of series 'S1'. Find the average of series 'T1'.Solution
Let six consecutive even numbers be 'a', (a + 2), (a + 4), (a + 6), (a + 8) and (a + 10), respectively.
ATQ,
a + a + 2 + a + 4 + a + 6 + a + 8 + a + 10 = 25 X 6
Or, 6a = 150 - 30
So, 'a' = (120 / 6) = 20
So, 2nd term of series 'T1' = 20 + 5 = 25
So, series 'T1' = 23, 25, 27, 29, 31
Therefore, required average = (23 + 25 + 27 + 29 + 31) ÷ 5 = 27
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