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    Question

    If the average of 7 back-to-back numbers is 65, find the

    sum of the first and last numbers.
    A 130 Correct Answer Incorrect Answer
    B 172 Correct Answer Incorrect Answer
    C 124 Correct Answer Incorrect Answer
    D 185 Correct Answer Incorrect Answer

    Solution

    ATQ,

    Assume the numbers are: (a - 3), (a - 2), (a - 1), a, (a + 1), (a + 2), (a + 3)

    Then, (a - 3 + a - 2 + a - 1 + a + a + 1 + a + 2 + a + 3) ÷ 7 = 65

    ⇒ (7a / 7) = 65

    ⇒ a = 65

    Sum of smallest and largest = (a - 3) + (a + 3) = 2a = 2 × 65 = 130

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