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      Question

      The average of the present age of 'A' and 'B' is 40

      years. If the ratio between the age of 'A' 5 years ago to the age of 'B' 5 years hence is 3:5, then find the age of 'B' 10 years hence.
      A 35 yrs Correct Answer Incorrect Answer
      B 42 yrs Correct Answer Incorrect Answer
      C 79 yrs Correct Answer Incorrect Answer
      D 55 yrs Correct Answer Incorrect Answer

      Solution

      ATQ,

      Let the age of 'A' 5 years ago be 3x years.

      Let the age of 'B' 5 years hence be 5x years.

      So, present age of 'A' = 3x + 5

      So, present age of 'B' = 5x - 5

      Sum of their present ages = 40 × 2 = 80

      So, 3x + 5 + 5x - 5 = 80

      So, 8x = 80

      So, x = 10

      So, present age of 'B' = 5x - 5 = 50 - 5 = 45

      Age of 'B' 10 years hence = 45 + 10 = 55 years

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