Question
There are three distinct numbers ‘p’, ‘q’ and ‘r’. If, p = 160, (p +
q) = 460 and (r –
q) = 80, then find the average of p, q and r.
Solution
Given, p = 160, (p + q) = 460 and (r – q) = 80 Therefore, q = 460 – 160 = 300 And, r = 300 + 80 = 380 Required average = (160 + 300 + 380)/3 = 840/3 = 280
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