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ATQ;
Let the three numbers be x, y, and z.
So,2x+y+z=350×2=700
x+2y+z=330×2=660
x+y+2z=310×2=620
Thus,
4×(x+y+z)=1980
x+y+z=495
Now,
x=700−495=205
y=660−495=165
z=620−495=125
Desired difference = 205−125=80
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