Question
The average of a set of 60 numbers was initially
calculated as 40. However, it was later discovered that two numbers were incorrectly recorded as 68 and 32, instead of the correct values 86 and 23. Determine the accurate mean after correcting these errors.Solution
Initially, mean of 60 numbers = 40
So, sum of 60 numbers = 60 X 40 = 2,400
ATQ, Correct sum = 2,400 - (68 + 32) + (86 + 23) = 2,409
Correct mean = (2,409/60) = 40.15
29% of 400 + 66% of 1100 - 50% of 1200 = ?Â
8 × 25% of ? = 400
36% of 250 + 26 ÷ 2 × ? = 207
36×?² + (25% of 208 +13) = 60% of 2400 + 17×18
15.8% of 9000 + 20.4% of 7500 = 30% of ?
32% of 4080 + 24% of 455 = x% of 4000
63 × 4 = ?2 – 1620 ÷ 5
53 – 8 = ? + 126
√256 * 3 – 15% of 300 + ? = 150% of 160