Question
The average of three numbers P, Q and R is 1600. R is
75% more than P. The ratio of P and Q is 4:5 respectively. If R is 25% less than S, then find out the number βSβ.Solution
The average of three numbers P, Q and R is 1600. P+Q+R = 1600x3 P+Q+R = 4800Β Β Eq.(i) The ratio of P and Q is 4:5 respectively. Letβs assume P and Q are β4yβ and β5yβ respectively. R is 75% more than P. R = 175% of P R = 175% of 4y R = 1.75 x 4y R = 7y Put the values of βPβ, βQβ and βRβ in the Eq.(i). 4y+5y+7y = 4800 16y = 4800 y = 300 If R is 25% less than S. R = (100-25)% of S 7y = 75% of S 7y = 0.75xS Put the value of βyβ in the above equation. 7x300 = 0.75xS 2100 = 0.75xS 2100/0.75 = S S = 2800
- Determine the final value of this expression:
(1/5) of {5β΄ - 24 Γ 14 + 12 Γ 18 - 10.5 of 10Β²} 3% of 842 ÷ 2% of 421 = ?
β225 + 27 Γ 10 + ? = 320
- Determine the value of βpβ if p = β529 + β1444
45 % of 180 + β144 * 8 = ?2 Β + 70 % of 80
Determine the value of 'p' in following expression:
720 Γ· 9 + 640 Γ· 16 - p = β121 X 5 + 6Β²- 7?2 = β20.25 Γ 10 + β16 + 32
- What will come in place of the question mark (?) in the following questions?
(2β΄ + 6Β²) Γ· 2 = ? 18(1/3) + 9(2/3) β 10(1/3) = 1(2/3) + ?