Question
The average weight of five friends A, B, C, D and E is
(x+8) years while the average weight of C and E is (x-8) kg. If the weight of another person F is also added, then average weight of all of them is reduced by 7 kg. Find the value of ‘x’ if average weight of A, B, D and F is 92.5 kg.Solution
Total weight of friends A, B, C, D and E = 5(x+8) kg Total weight of friends C, and E = 2(x- 8) kg So, Total weight of A, B and D = 5(x+8) - 2(x-8) = (3x+56) kg Weight of F = [(x+8-7)×6] - [5(x+8)] => F = (x-34) kg According to the question, => (3x+56) + (x-34) = 92.5 × 4 => 4x + 22 = 370 => 4x = 348 => x = 87
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