Question
The average weight of 4 persons is 66 kg. The heaviest
person’s weight is 32 kg more than the lightest person’s weight. If the average weight of the rest two persons is 70 kg, then find the weight of the heaviest person.Solution
The sum of the weight of 4 persons = 66 × 4 = 264 kg Let the weight of the lightest person = ‘x’ kg The weight of the heaviest person = (x + 32) kg The sum of the weight of the remaining two persons = 70 × 2 = 140 kg According to the question, x + x + 32 + 140 = 264 2x = 92 x = 46 The weight of the heaviest person = 46 + 32 = 78 kg
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